下面的程序从用户那里获取一个整数输入,并生成多达 10 的乘法表。
#include <stdio.h> int main() { int n, i; printf("Enter an integer: "); scanf("%d", &n); for (i = 1; i <= 10; ++i) { printf("%d * %d = %d \n", n, i, n * i); } return 0; }
结果:
Enter an integer: 8
8 * 1 = 8
8 * 2 = 16
8 * 3 = 24
8 * 4 = 32
8 * 5 = 40
8 * 6 = 48
8 * 7 = 56
8 * 8 = 64
8 * 9 = 72
8 * 10 = 80
Process returned 0 (0x0) execution time : 1.964 s
Press any key to continue.
除教程外,本网站大部分文章来自互联网,如果有内容冒犯到你,请联系我们删除!