C语言练习：计算一个实数的n次方

C语言练习：计算一个整数的n次方. 计算一个数的幂

For example: In the case of 2³

• 2 is the base number
• 3 is the exponent
• And, the power is equal to 2*2*2

1. 利用while loop

#include <stdio.h>
int main() {
    int base, exp;
    long double result = 1.0;
    printf("Enter a base number: ");
    scanf("%d", &base);
    printf("Enter an exponent: ");
    scanf("%d", &exp);

    while (exp != 0) {
        result *= base;
        --exp;
    }
    printf("Answer = %.0Lf", result);
    return 0;
}

Enter a base number: 3
Enter an exponent: 4
Answer = 81

2. 利用pow()函数

#include <math.h>
#include <stdio.h>

int main() {
    double base, exp, result;
    printf("Enter a base number: ");
    scanf("%lf", &base);
    printf("Enter an exponent: ");
    scanf("%lf", &exp);

    // calculates the power
    result = pow(base, exp);

    printf("%.1lf^%.1lf = %.2lf", base, exp, result);
    return 0;
}

Enter a base number: 2.3
Enter an exponent: 4.5
2.3^4.5 = 42.44

学究

程序员和搬砖者，开发研制FPGA开发板和芯片CPU,  奇门遁甲，阴阳五行，周易八卦的学习者