C语言检查输入数据是不是阿姆斯壮数

阿姆斯壮数(armstrongnumber) 定义：阿姆斯壮数(armstrongnumber) 是等于其数字的立方数之和的数字，例如：0，1，153，370，371，407等。
现在试着理解为什么153是一个阿姆斯壮数字， 153 = (1*1*1)+(5*5*5)+(3*3*3)。

153 = (1*1*1)+(5*5*5)+(3*3*3)
(1*1*1)=1
(5*5*5)=125
(3*3*3)=27
So:
1+125+27=153

C语言检查输入数据是不是阿姆斯壮数

#include<stdio.h>
int main()
{
   int num,copy_of_num,sum=0,rem;

   //Store input number in variable num
   printf("\nEnter a number:");
   scanf("%d",&num);

   /* Value of variable num would change in the
      below while loop so we are storing it in
      another variable to compare the results
      at the end of program
   */
   copy_of_num = num;

   /* We are adding cubes of every digit
    * and storing the sum in variable sum
    */
   while (num != 0)
   {
      rem = num % 10;
      sum = sum + (rem*rem*rem);
      num = num / 10;
   }

   /* If sum of cubes of every digit is equal to number
    * itself then the number is Armstrong
    */
   if(copy_of_num == sum)
      printf("\n%d is an Armstrong Number",copy_of_num);
   else
      printf("\n%d is not an Armstrong Number",copy_of_num);
   return(0);
}

Enter a number:371

371 is an Armstrong Number
Process returned 0 (0x0) execution time : 4.139 s
Press any key to continue.

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