使用递归函数发现两个数的最小公倍数
#include <stdio.h>
int hcf(int n1, int n2);
int main() {
int n1, n2;
printf("Enter two positive integers: ");
scanf("%d %d", &n1, &n2);
printf("G.C.D of %d and %d is %d.", n1, n2, hcf(n1, n2));
return 0;
}
int hcf(int n1, int n2) {
if (n2 != 0)
return hcf(n2, n1 % n2);
else
return n1;
}
结果
|
1 2 3 |
Enter two positive integers: 366 60 G.C.D of 366 and 60 is 6. |
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