使用递归函数发现最小公倍数

使用递归函数发现两个数的最小公倍数

#include <stdio.h>
int hcf(int n1, int n2);
int main() {
    int n1, n2;
    printf("Enter two positive integers: ");
    scanf("%d %d", &n1, &n2);
    printf("G.C.D of %d and %d is %d.", n1, n2, hcf(n1, n2));
    return 0;
}

int hcf(int n1, int n2) {
    if (n2 != 0)
        return hcf(n2, n1 % n2);
    else
        return n1;
}

结果

Enter two positive integers: 366
60
G.C.D of 366 and 60 is 6.

学究

程序员和搬砖者，开发研制FPGA开发板和芯片CPU,  奇门遁甲，阴阳五行，周易八卦的学习者